Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(x1) → b(x1)
b(b(c(x1))) → c(c(a(a(a(x1)))))
c(x1) → x1

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

a b c b c c → a b c b c c a a a

a b c b c c → a b c b c c a a a
by OverlapClosure OC 2

a b c b c → a b c b b b
by OverlapClosure OC 3

a b c b c → a b c b a b
by OverlapClosure OC 3

a b c b c → a b c a a b
by OverlapClosure OC 3

a b c b c → a a c a a b
by OverlapClosure OC 2

a b c b c → a a c a a a
by OverlapClosure OC 2

a → b
by original rule (OC 1)

b b c b c → a a c a a a
by OverlapClosure OC 2

b b c → a a a
by OverlapClosure OC 3

b b c → c a a a
by OverlapClosure OC 3

b b c → c c a a a
by original rule (OC 1)

c →
by original rule (OC 1)

c →
by original rule (OC 1)

a b c → c a a a
by OverlapClosure OC 2

a → b
by original rule (OC 1)

b b c → c a a a
by OverlapClosure OC 3

b b c → c c a a a
by original rule (OC 1)

c →
by original rule (OC 1)

a → b
by original rule (OC 1)

a → b
by original rule (OC 1)

a → b
by original rule (OC 1)

a → b
by original rule (OC 1)

b b c → c c a a a
by original rule (OC 1)

(2) NO